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Explain average rate or reaction for hypothetical Rto P reaction. |
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Answer» Solution :Consider a hypothetical reaction ,assuming that the volume of the system remain constant. Reaction:`RtoP` Suppose at `t_(1)` time concentration of R=`[R]_(1)` Suppose at `t_(2)` time concentration of R=`[R]_(2)` So `Deltat=(t_(2)-t_(1))` Decrease in concentration of reactant `DeltaR=[R]_(2)-[R]_(1)` `therefore` The rate of decrease in concentration of reactant `R=-(Delta[R])/(Deltat)=("decrease in concentration of R")/("time required for that")` ......(i) At `t_(2)` time concentration of product =`[P]_(1)` So in `Deltat=(t_(1)-t_(1))` INCREASE in concentration of product is `DeltaP=[P]_(2)-[P]_(1)` `P=("Increase in concentration of P")/("time require for that")+(Delta[P])/(Deltat)`.....(ii) From EQUATION (i) and (ii) `"Average rate"=(Delta[R])/(DETAT)=+(Delta[P])/(Deltat)` Note:(i)In equation [ ]indicate concentration . (ii)Since `Delta[R]` is negative QUANTITY (as concentration is decreasing).It is multipled with -1 to make the rate of reaction a positive quantity. |
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