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Explain briefly, the action of a transistor as a switch. |
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Answer» Solution :i. the transistro is MADE to function in the cutt-off region and in the saturation region ii. In the above circuit, `V_("BB") = V_(i) = I_(B) R_(B) + V_(CE) = V_("CC") - I_(C)R_(C) = V_(0)` iii.The transistor will be in the cut-off region as long as the INPUT voltage is LESS than the `V_("BE")` = 0.65V for silicon and 0.25 V for germanium. The transistor acts as an open switch `V_(B) = V_("CC")` iv. For a transistor operated at saturated region, `V_("CE") ~~ V_(CE) ~~ 0.`the transistor acts as a closed switch. 
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