Saved Bookmarks
| 1. |
Explain [Co(NH_(3))_(6)]^(3+) is an inner orbital complex whereas [Ni(NH_(3))_(6)]^(2+) is an outer orbital complex. |
|
Answer» Solution :In `[Co(NH_(3))_(6)]^(3+)`, oxidation STATE of `Co=+3` Electronic CONFIGURATION `=3d^(6)` In presence of `NH_(3)`, `3d` electrons pair up leaving two `d`-orbitals empty. HENCE , the hybridisation is `d^(2)sp^(3)` forming an inner orbital complex. In `[Ni(NH_(3))_(6)]^(2+)` Oxidation state `=+2`, Electronic Configuration `=3d^(8)`. In the presence of `NH_(3)`, `3d` electrons do not pair up. The hybridisation involved is `sp^(3)d^(2)` and it forms an outer orbital complex. |
|