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| 1. |
Explain (Co(NH_(3))_(6)]^(3+) is an inner orbital complex whereas [NI(NH_(3))_(6)]^(2+) is an outer orbital complex. |
| Answer» Solution :In `[Co(NH_(3))_(6)]^(3+)` Co is in +3 STATE with the configuration `3d^(6)` In the PRESENCE of `NH_(3)` 3d electrons pair up LEAVING two d - orbitals empty. Hence, the hybridization is dspo forming an inner orbital complex. In `[Ni(NH_(3))_(6)]^(2+)` Ni is in +2 state with the configuration `3d_(8)`. In presence of `NH_(3)` the 3d electrons, do not pair up. The hybridization involved is `sp^(3)d^(2)` forming an outer orbital complex | |