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Explain construction of Daniel cell. Write half cell reactions. How is Daniel cell symbollically represented? |
Answer» Solution : At anode zinc gets oxidised. ELECTRONS flow through external CIRCUIT. At cathode `CU^(+2)` IONS get reduced. At anode: `Zn to Zn^(+2)+2e^-` At cathode: `Cu^(+2)+2e^(-) to Cu` `Zn(s)|Zn^(+2) (aq) ||Cu^(+2) (aq) |Cu(s)` (s and aq are not value points) |
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