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Explain Heisenberg's uncertainty principle. |
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Answer» Solution :Position of particle (electron or other) and momentum cannot be MEASURED simultaneously at a time. There is always uncertainty in position `(Deltax)`and in momentum `(Deltap)`. `therefore Deltax.Deltap~~h` `Deltax.Deltap~~(h)/(2pi)`…..(1) Where `h=(h)/(2pi)` Fromequation (1) if `Deltaxto0` then `Deltapto"Infinity"` and when `Deltapto0` then `Deltaxto"infinity"` By MAKING on quantity definite another quantity became undefinite.This is REALITY of microscopic particles. If electron posses definite momentum p (i.e. `Deltap`=0) then it ha definite wavelength `LAMBDA`. `lambda=(h)/(p)` A wave of definite (single) wavelength EXTENDS all over space. That is its position uncertainty is infinite `(Deltaxtooo)` which is consistentwith the uncertainty principle. |
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