Saved Bookmarks
| 1. |
Explain how will you find activation energy of a reaction by graphical method. (or) Draw the graph between log k vs (1)/(T). What is the relationship between its slope and acitivation energy. |
Answer» Solution :A plot of log K against `(1)/(T)` VALUES gives a straight line with slope value equal to - `E_(a)//2.303 R` and intercept value equals to log A. (II) The plot gives a NEGATIVE slope straight line also. (iii) From the slope of straight line `E_(a)` can be calculated. |
|