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Explain lateral shift for the refraction from rectangular glass slab. |
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Answer» Solution :For a rectangular slab, refraction takes place at two interfaces (air-glass and glass-air). It is easily seen from figure that `r_2 = i_1`. i.e., the emergent ray is PARALLEL to the incident ray there is no deviation but it does SUFFER LATERAL displacement/shift with respect to the incident ray. Here, emergent ray is parallel to incident ray hence`i_1=r_2`. Thus, there is no deviation of incident ray but it experiences the lateral shift as compared to incident ray. For more information : If lateral shift is x, then `x=txxi_2(1-n_1/n_2)` where t = THICKNESS of slab `n_1` = REFRACTIVE index of rarer medium (air) `n_2` = refractive index of denser medium (glass) `i_1` = incidence angle |
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