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Explain mutual induction and derive equation of induced emf. |
Answer» Solution :As shown in FIGURE when current from coil `C_2` changes then flux linked with coil `C_1` also GET CHANGED and emf is induced in coil`C_1`.  If number of turns in `C_1` is `N_1` then net flux `N_1Phi_1 prop I_2` `THEREFORE N_1Phi_1=MI_2` ACCORDING to Faraday.s law an emf `epsilon_1` is induced in coil-1 which is given by `epsilon_1=-(dN_1Phi_1)/(dt)-d/(dt)(M_12I_2)` `therefore epsilon_1=-M_12(dI_2)/(dt)` Similarly we can prove `epsilon_2=-M_21(dI_1)/(dt)` |
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