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Explain on the basis of valence bondy theory that [Ni(CN)_(4)]^(2-) ion with square planar structure is diamagnetic and the [NiCl_(4)]^(2-) ion with tetrahedral geometry is paramagnetic. |
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Answer» Solution :Nickel in `[Ni(CN)_(4)]^(2-)` is in the `+2` oxidation state , i.e. Nickel is persent as `Ni^(+2)` ion. `dsp^(2)`-hybrid orbitals -Diamagnetic `CN^(-)` is a strong ligand as it approaches the metal ion , So the electrons should getpaired up. In `[NiCl_(4)]^(2-)`, `CL^(-)` provides a WEAK ligand field. It is therefore UNABLE to pair up the unpaired electrons of the `3D` orbital. Hence the hybridisation is `SP^(3)` and it is paramagnetic . 
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