1.

Explain the action of acidified K_(2)C_(2)O_(7) with (i) Sulphur dioxide (ii) Alcohols.

Answer»

Solution :(i) ACIDIFIED `K_(2)C_(2)O_(7)` oxidises So, to sulphate ion.
`Cr_(2)O_(7)^(2-) +3SO_(2)+ 2H^(+) to 2CR^(3+)+ 3SO_(4)^(2-)+ H_(2)O`
(ii) Acidified`K_(2)C_(2)O_(7)` oxidises alcohol to acid.
`2K_(2)C_(2)O_(7) + 8H_(2)SO_(4)+ UNDERSET("Ethanol")(3CH_(3)CH_(2)OH) to 2K_(2)SO_(4)+ 2Cr_(2)(SO_(4))_(3)+ underset("ACETIC acid")(3CH_(3)COOH)+ 11H_(2)O`


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