1.

Explain the action of acidified K_(2)C_(2)O_(7) with (i) Iodide (ii) Sulphide

Answer»

Solution :(i) Acidified `K_(2)C_(2)O_(7)` OXIDISES iodide ions to iodine.
`Cr_(2)O_(7)^(2-)+ 6I^(-)+ 14H^(+) to 2Cr^(3+)+ 3I_(2)+ 7H_(2)O`
(II) Acidified `K_(2)C_(2)O_(7)`oxidises Sulphido ions to Sulphur,
`Cr_(2)O_(7)^(2-)+ 3S^(2-)+ 14H^(+) to 2Cr^(3+)+ 3S+ 7H_(2)O`


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