Explain the action of conc. HCl on KMnO_(4) crystals. – InterviewSolution

1.	Explain the action of conc. HCl on KMnO_(4) crystals.
Answer» Solution :When `KMnO_(4)` is treated with CONC. `HCl` Chlorine is LIBERATED. `2KMnO_(4)+16HCl rarr 2KCl+2MnCl_(2)+8H_(2)O+5Cl_(2)`

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