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Explain the following facts giving appropriate reason in each case : (i) NF_(3) is an exothermic compound whereas NCl_(3) is not. (ii) All the bonds in SF_(4) are not equivalent. |
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Answer» Solution :(i) The high enthalpy of formation of `NCl_(3)`, is due to large difference in the size of the N and Cl atoms, as nitrogen belongs to second period and Cl atoms belongs to third period, this large difference makes the `N - Cl` bond WEAK and requires energy during its formation, so it is an ENDOTHERMIC compound. But in `NF_(3)`, since the size of the atoms is small, as both the atoms belong to second period, therefore, the `N - F` bond is strong and its formation is spontaneous, so it is an exothermic compound. (II) This is so because `SF_(4)` has see - saw shape and bonds are not equivalent on account of bond pair - lone pair repulsion . With S at the center , one of the three equatorial positions is occupied by a non bonding lone pair of ELECTRONS with two different types of F ligands, two axial and two equatorial. Axial Bonds suffer more repulsion than equatorial bonds as they are repelled by both bonding and non bonding electrons. Thus , the bonds are not equivalent in `SF_(4)`. |
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