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Explain the following : (i) NO_(2) readily forms a dimer. (ii) BiCl_(3) is more stable than BiCl_(5). |
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Answer» Solution :(i) It is because`NO_(2)` contains odd number of valence electrons. On dimerisation, it is converted to STABLE `N_(2)O_(4)` molecule with even number of electrons. (ii) In GROUP - 15 the stability of `+5` OXIDATION state decreases and that of `+3` oxidation state increases due to inert PAIR effect. Thus, `BiCl_(3)` is more stable than `BiCl_(5)`. |
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