1.

Explain the hydrolysis of 2-bromobutane with aqueous KOB.

Answer»
  • 2-bromobutane is optically active and it undergoes SN1 reaction with aqueous KOH.
  • The product obtained will be an optically inactive racemic mixture. 
  • As nucleophilic reagent OH- ion can attack the carbocation from both sides to form equal proportions of dextro and levo rotatory optically active isomers, it results in the formation of optically inactive racemic mixture


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