Explain the hydrolysis of 2-bromobutane with aqueous KOB.
Answer»
2-bromobutane is optically active and it undergoes SN1 reaction with aqueous KOH.
The product obtained will be an optically inactive racemic mixture.
As nucleophilic reagent OH- ion can attack the carbocation from both sides to form equal proportions of dextro and levo rotatory optically active isomers, it results in the formation of optically inactive racemic mixture