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Explain the mechanism of oxidation of HCl by air in the presence of CuCl_(2). |
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Answer» Solution :`UNDERSET("CATALYST")(2CuCl_2) to underset("Product")(Cl_2) + Cu_2Cl_2` `2Cu_2Cl_2 + underset("REACTANT")(O_2) to underset("Intermediate CPD/")(2Cu_2OCl_2)` `2Cu_2OCl_2 + underset("Reactant")(4HCl) to underset("Product")(2H_2O) + underset("Catalyst")(4CuCl_2)` |
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