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Explain the observable change taking place during reaction of iron with the aqueous solutions ofH_(2)SO_(4) and CuSO_(4) respectively. |
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Answer» Solution :Fe on treatment with `H_(2)SO_(4)`liberates hydrogen gas. `Fe+H_(2)O_(4)toFeSO_(4)toH_(2)uarr` The solution turnsgree due to the FORMATION of `FeSO_(4)`. As Feis more reactive than Cu , it displace Cu from `CuSO_(4)` solution .Hence blue colour of`CuSO_(4)`solution disappears. `Fe+CuSO_(4)(AQ)toFeSO_(4)+Cu` |
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