Explain the rate of reaction with energy of activation and temperature with the help of Arrhenius equation state its importance .

Explain the rate of reaction with energy of activation and temperature

1.	Explain the rate of reaction with energy of activation and temperature with the help of Arrhenius equation state its importance .
Answer» Solution :The EQUATION of correspond relation between rate of chemical reaction and temperature is given by Arrhenius k=`Ae^(-(E_(a))/(RT))` Where ,k=Rate constant of reaction `prop` Rate `E_(a)`=Activation ENERGY J `K^(-1) mol^(-1)` T=Absolute temperature R=gas constant =8.314 J `mol^(-1) K^(-1)` A=Arrhenius frequency =Frequency factor Pre expancial factor Taking natural logarithm of both side of above reaction. In K=`(-E_(a))/(RT)`+In A The equation is y=mx+c,straight line type . The PLOT of in `kto(1)/(T)` is obtaine by following figure.The plot is straight line and forn negative slope and intercept. Calculation of `E_(a)` and A:In fig. the slop= `(-E_(a))/(R)`=In A. So calculate `E_(a)` and A USING these values. According to Arrhenius equation : `-E_(a)prop(1)/(T)` (Means,Increasing the temperature or decreasing the activarion energy `E_(a)`) k=Rate `prop` T (Increase the temperature so rate is increase) K=Rate `prop(1)/(E_(a))` (Activation eneergy is less so,Rate is more)