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Explain the relation between rate of reaction and stoichiometric coefficients of balance chemical equation with examples. |
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Answer» Solution :If the reactant and product each have stoichiometric COEFFICIENT one than each has one mole stoichiometric .So representation of rate is easy:`RtoP` reaction. `r_(av)=-(Delta[R])/(Deltat)=(Delta[P])/(Deltat)` eg. `Hg_(l)+Cl_(2(g))to HgCl_(2(s))` Velocity=`-(Delta[Hg])/(Deltat)=-(Delta[Cl_(2)])/(Deltat)=(Delta[HgCl_(2)])/(Deltat)` If stoichiometric co-efficients are DIFFERENT and not one then the rate is divided by their respective stoichiometric coefficient. eg.-1:`2HI_((g))toH_(2(g))+I_(2(g))` Velocity =`-(1)/(2)-(Delta[HI])/(Deltat)=(Delta[H_(2)])/(Deltat)=(Delta[I_(2)])/(Deltat)` eg-2:`2NH_(3(g))toN_(2(g))+3H_(2(g))` `therefore` Rate of reaction =`-(1)/(2)-(Delta[NH_(3)])/(Deltat)=(Delta[N_(2)])/(Deltat)=(1)/(3)-(Delta[H_(2)])/(Deltat)` |
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