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Explain the theory of interference of light. |
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Answer» Solution :Let `Y_(1)=asinomegat` and `Y_(2)=bsin(omegat+phi)` be two light waves interfere GIVING rise to RESULTANT `Y=Y_(1)+Y_(2)` NET displacement from principle of superposition `Y=Y_(1)+Y_(2)` `Y=asinomegat+bsin(omegat+phi)=asinomegat+b(sinomegatcosphi+cosomegatsinphi)` `=sinomegat(a+bcosphi)+bsinphicosomegat` Let `a+bcosphi=Rcostheta` and `bsinphi=Rsintheta` `Y=Rsinomegatcostheta+Rcosomegatsintheta=Rsin(omegat+theta)` `R=sqrt(a^(2)+b^(2)+2abcostheta)` OR the wave with equal amplitude must be considered. `R=sqrt(2a^(2)+2B^(2)+2acostheta)=2acos.(theta)/(2)` |
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