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Explain the variation in E_(M^(2+)//M^(3+)+ 3d series |
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Answer» Solution :1. In transition series, as we move down from Ti to Zn, the standard REDUCTION potential `E_(M^(2+)//M^(3+)` value is approaching towards less negative value and copper has a positive reduction potential. i.E. elemental copper is more stable than `CU^(2+)`, 2. `E_(M^(2+)//M^(3+)` value for manganese and zinc are more negative than regular TREND. It is due to extra stability ARISES due to the half filled d configuration in `Mn^(2+)` and completely filled `d^(10)` configuration in `Zn^(2+)` 3. The standard electrode potential for the`M^(3+)//M^(2+)`half cell gives the relative stability between`M^(3+)` and `M^(2+)` 4. The high reduction potential of`M^(3+)//M^(2+)`indicates `M^(2+)` is more stable than `M^(3+)`, 5. For `Fe^(3+)//Fe^(2+)` the reduction potential is 0.77 V, and this low value indicates that both `Fe^(3+)` and `Fe^(2+)` can exist under normal condition. 6. `Mn^(3+)` has a `3d^(4)` configuration while that of `Mn^(2+)` ss `3d^(5)`. The extra stability associated with a half filled d sub-shell makes the reduction of `Mn^(3+)` very feasible [`E^(0) = +1.511`] |
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