Saved Bookmarks
| 1. |
Explain why compounds of Cu^(2+) are coloured but those of Zn^(2+) are colourless. |
|
Answer» Solution :Cu (Z = 29) Electronic configuration is [Ar]`3d^(10) 4s^(1)` `Cu^(2+)` : Electronic configuration is [Ar]`3d^(9)`. In `Cu^(2+)` promotion of electrons take place in outer d-orbital by the absorption of light form visible region involves d - d transition. Due to this `Cu^(2+)` compounds are coloured. Where in `Zn^(2+)` electronic configuration is `[Ar]3d^(10)`. It has completely FILLED d-orbital. So there is no chance of d-d transition. So `Zn^(2+)` compounds are COLOURLESS. |
|