1.

Explain why tanA tanB/1-tanAtanB is undefined when A=pie/6, B=pie/3?

Answer»

nB/1-tanAtanBWhen A=π/6 and B=π/3put the valuetanπ/6 tanπ/3 /1- tanπ/6 tanπ/31/√3 ×√3   1-1/√3×√31/1-1⇒1/0=∞=which cannot be DEFINED



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