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Explain why Zn on reaction with dil. H_(2)SO_(4) liberated hydrogen, whereas copper cannot? |
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Answer» Solution :(i) Any metal above hydrogen in the electrochemical SERIES is a weaker reducing agent than hydrogen and will not CONVERT `H^(+) " to " H_(2)`. (ii) This EXPLAINS why Zn lying below hydrogen reacts with DIL. `H_(2)SO_(4)` to liberate `H_(2)`, while Cu lying above hydrogen does not react. `Zn+2H^(+)(dil.H_(2)SO_(4)) rarr Zn^(2+)+H_(2) uarr Cu+2H^(+)(dil.H_(2)SO_(4))Cu^(2+)+H_(2)` |
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