1.

Explain why Zn shown only +2 oxidation state.

Answer»

SOLUTION :E.C. of Zn `Zn = [Ar]^(18) 3d^(10) 4s^(2)` . After loss of `2e^(-)` of FORM `Zn^(2+)` , it acquires stable electronic configuration of `3d^(10)` ( fully -filled). Hence, it shows oxidation STATE of `+2` only.


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