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Explain with equations, the react ion of sulphuric acid with ethyl alcohol under different conditions. |
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Answer» Solution :Equations for reaction of sulphuric acid with ethyl alcohol at different temperatures are given below : (i) `C_(2)H_(5)OH overset("conc. "H_(2)SO_(4))UNDERSET("ROOM temp.")rarr underset("sulphate")underset("Ethyl hydrogen")(C_(2)H_(5)HSO_(4))+H_(2)O` (ii) `2C_(2)H_(5)OH overset("conc. "H_(2)SO_(4))underset(383K)rarr underset("Diethyl sulphate")((C_(2)H_(5))_(2)SO_(4))+2H_(2)O` (iii) `2C_(2)H_(5)OH overset("conc. "H_(2)SO_(4))underset(413K)rarr underset("Ethoxyethane")(C_(2)H_(5)OC_(2)H_(5))+H_(2)O` (iv) `C_(2)H_(5)OH overset("conc. "H_(2)SO_(4))underset(443K)rarr underset("ETHENE")(CH_(2)=CH_(2))+H_(2)O` |
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