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Explainwhy Cr^(2+) stronglyreducingwhileMn^(3+) isstronglyoxidizing . |
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Answer» Solution :(I ) `Cr^(2+)` is stronglyreducing in nature. Ithasa `d^(4)`CONFIGURATION. Whileacting asa reducingagent, itgetsoxidizedto `Cr^(3+)` (ELECTRONICCONFIGURATION`d^(3)`) (II)This `d^(3) ` configurationcan be writtenas `3t^(2g)` configurationwhichis a morestableconfiguration. (III)In the caseof `Mn^(3+)(d^(4))` it actsas anoxidizingagentand getsreduced to `Mn^(2+) (d^(5))` (iv )THISHAS anexactly half- filledd- orbitaland hasan extrastability. |
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