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Express sin 12θ + sin 4θ as the product of sines and cosines. |
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Answer» Given, \(sin12θ+sin4θ\) = \(2sin(\frac{12θ+4θ}{2})cos(\frac{12θ-4θ}{2})\) = \(sin8θcos4θ\) [Using the formulae \(sinC+sinD\) \(=2sin(\frac{C+D}{2})cos(\frac{C-D}{2})\)] |
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