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Express the following in `a + ib` form: (i) `((cos theta+ isin theta)/(sin theta + icos theta))^(4)` (ii)` ((cos 2theta -isin2theta)^(4)(cos4theta +isin4theta)^(-5))/((cos 3theta +isin3theta)^(-2) (cos 3theta -isin 3theta)^(-9))` (iii) ` ((sinpi//8 +icos pi//8)^(8))/((sinpi//8-icospi//8)^(8))` |
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Answer» (i) `((costheta+isintheta)/(sintheta+icostheta))^(4)=((costheta+isintheta)^(4))/(i^(4)(costheta-isintheta)^(4))` `=((costheta+isintheta)^(4))/((costheta+isintheta)^(-4))` `=(cos8theta+isintheta)^(8)` `=cos8theta+isin8theta` (ii) `((cos2theta-isin2theta)^(4)(cos4theta+isin4theta)^(-5))/((cos3theta+isin3theta)^(-2)(cos3theta-isin3theta)^(-9))` `=([(costheta+isintheta)^(-2)]^(4)[(costheta+isintheta)^(4)]^(-5))/([(costheta+isintheta)^(3)]^(-2)[(costheta+isintheta)^(-3)]^(-9))` `=((costheta+isintheta)^(-8)(costheta+isintheta)^(-20))/((costheta+isintheta)^(-6)(costheta+isintheta)^(27))` `=(costheta+isintheta)^(-8-20+6-27)` `=(costheta+isintheta)^(-49)` `=cos49theta-isin49theta` (iii) `((sinpi//8+icospi//8)^(8))/((sinpi//8-icospi//8)^(8))` `(i^(8)(cospi//8-isinpi//8)^(8))/((-i)^(8)(cospi//8+isinpi//8)^(8))=(cospi-isinpi)/(cospi+isinpi)=1` |
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