1.

Express the following in S.I. base units using power of 10 notation (example 2.54 mm = 2.43xx10^(-3)m) (a)1.35mm(b)"1 day"(c)" 6.45 mL "(d) 48mug (e) 0.0426" in"

Answer»

Solution :S.I. unit of length is 'm'
1 m = 100 cm, 1 cm = 10 mm
`therefore" Unit CONVERSTION FACTORS are"=(1m)/(100cm)=(100cm)/(1m)=1, (1cm)/(10mm)=(10mm)/(1cm)=1`
`therefore""1.35mm=1.35mmxx(1cm)/(10mm)xx(1m)/(100cm)=1.35xx10^(-3)m`
(b) S.I. units of TIME is 'sec' (s)
`1day=1dayxx(24hour)/(1day)xx(60min)/(1HOUR)xx(60s)/(1min)=8.6400xx10^(4)s`
(c) S.I. units of volume is `'m^(3)'`
`6.45mL=6.45mLxx(1cm^(3))/(1mL)xx(1m)/(100cm)xx(1m)/(100cm)xx(1m)/(100cm)=6.45xx10^(-6)m^(3)`
(d) S.I. unit of mass is 'kg'
`48mug=48mugxx(10^(-6))/(1mug)xx(1kg)/(1000g)=4.8xx10^(-8)kg`
(e) S.I. units of length is 'm'
`0.0426"in"="0.0426 in"xx(2.54cm)/("1 in ")xx(1m)/(100cm)=1.082xx10^(-3)m`


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