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Express the given number 2.232323.... can be expressed in the form p /q , where p and q areintegers and q≠ 0. |
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Answer» ANSWER : x=0.2353535... x=0.2353535...10x=2.353535... x=0.2353535...10x=2.353535...100x=23.53535... x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535... x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535... x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233 x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990 x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in q x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in QP x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in qp x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in qp
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