Express the input voltages v1 and v2 in terms of differential input (vd) and common-mode input(vc). Given v2 > v2.(a) Vd = V1 – V2, Vc = 0.5(V1 + V2)(b) Vd = V2 – V1, Vc = V1 + V2(c) Vd = V1 – V2, Vc = V1 + V2(d) Vd = V2 – V1, Vc = 0.5(V1 + V2)The question was posed to me by my college director while I was bunking the class.My question is taken from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits

Express the input voltages v1 and v2 in terms of differential input (v

1.	Express the input voltages v1 and v2 in terms of differential input (vd) and common-mode input(vc). Given v2 > v2.(a) Vd = V1 – V2, Vc = 0.5(V1 + V2)(b) Vd = V2 – V1, Vc = V1 + V2(c) Vd = V1 – V2, Vc = V1 + V2(d) Vd = V2 – V1, Vc = 0.5(V1 + V2)The question was posed to me by my college director while I was bunking the class.My question is taken from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits
Answer» Correct choice is (d) VD = V2 – V1, VC = 0.5(V1 + V2) The best I can EXPLAIN: This is the correct mathematical representation.

Discussion

No Comment Found

Related InterviewSolutions

Determine the voltage gain for the given circuit known that R1 = R3 = 10kΩ abd R2 = R4 = 100kΩ.(a) 1(b) 10(c) 100(d) 1000This question was posed to me in semester exam.The doubt is from Difference Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits
The expression for the integration frequency is(a) CR(b) 1/CR(c) R/C(d) C/RI had been asked this question in semester exam.My question comes from Integrators and Differentiators in division Operational Amplifiers of Electronic Devices & Circuits
For operation with 10-V output pulses with the requirement that the sum of the rise and fall times represent only 20% of the pulse width (at half amplitude), what is the slew-rate requirement for an op amp to handle pulses 2 µs wide? (Note: The rise and fall times of a pulse signal are usually measured between the 10%- and 90%-height points.)(a) 10 V/µs(b) 20 V/µs(c) 40 V/µs(d) 80 V/µsI had been asked this question during a job interview.Origin of the question is Large Signal Operations on operational Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits
For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)(a) (1+R2/R1)/(1+((1+R2/R1)/A))(b) (R2/R1)/(((1+R2/R1)/A))(c) (1+R2/R1)/(((1+R2/R1)/A))(d) (R2/R1)/(1+((1+R2/R1)/A))I got this question at a job interview.Asked question is from The Non Inverting Configuration topic in section Operational Amplifiers of Electronic Devices & Circuits
For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2 is the positive terminal v1 is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?(a) v1= 1.99V, v2= 2.00V, v0 = 1.00V(b) v1= 1.00V, v2= 1.00V, v0 = 0V(c) v1= 1.00V, v2= 1.10V, v0 = 10.1V(d) v1= 0.99V, v2= 2.00V, v0 = 1.00VThis question was addressed to me during an online exam.My question is from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits
The units of the full power bandwidth is(a) Watt(b) Joule(c) Seconds(d) HertzI have been asked this question during an interview.My question comes from Large Signal Operations on operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits
In an ideal op amp the open-loop gain is 10^3. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2 = 0V and v3 = 2V where it is assumed that v1 and v2 are input terminals and v3 is the output terminal. The value of the differential (vd) and common-mode (vcm)signal is(a) Vd = 2 mV and vcm = 1 mv(b) Vd = 2 mV and vcm = -1 mV(c) Vd = 2 mV and vcm = 2mV(d) Vd = 2 mV and vcm = -2mVThis question was posed to me during an online exam.Asked question is from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits
An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.(a) 0.1 MHz and -60 db(b) 10 MHz and -60 db(c) 10 MHz and 60 db(d) 1 MHz and 60 dbThe question was asked during an interview for a job.I want to ask this question from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance topic in section Operational Amplifiers of Electronic Devices & Circuits
The frequency transfer function of a differentiator is given by(a) jωCR(b) 1/jωCR(c) – jωCR(d) – 1/jωCRI had been asked this question in semester exam.My doubt stems from Integrators and Differentiators topic in section Operational Amplifiers of Electronic Devices & Circuits
For the difference amplifier shown below, let all the resistors be 10kΩ ± x%. The expression for the worst-case common-mode gain is(a) x / 50(b) x / 100(c) 2x / (100 – x)(d) 2x / (100 + x)I had been asked this question in exam.My enquiry is from Difference Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment