1.

Express the rate of following reaction in terms of different reactancts andproducts of 4NH_(3)(g)+5O_(2)(g)to4NO(g)+6H_(2)O(g) If the rate of formation of NO is 3.6xx10^(-3)molL^(-1)s^(-1),calculate (i) the rate of disappearance of NH_(3). (ii)the rate of formation of H_(2)O

Answer»

SOLUTION :`(i)` Rate of reaction `=-(1)/(4)(d[NH_(3)])/(dt)=-(1)/(5)(d[O_(2)])/(dt)=(1)/(4)(d[NO])/(dt)=+(1)/(6)(d[H_(2)O])/(dt)`
Rate of DISAPPEARANCE of `NH_(3)=` Rate of formation of `NO`
`=3.6xx10^(-3)mol L^(-1)s^(-1)`
Rate of formation of `H_(2)O=(6)/(4)xx` Rate of formation of `NO`
`IMPLIES(d[H_(2)O])/(dt)=(3)/(2)xx3.6xx10^(-3)`
`=5.4xx10^(-3)molL^(-1)s^(-1)`.


Discussion

No Comment Found