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Express the rate of following reaction in terms of different reactancts andproducts of 4NH_(3)(g)+5O_(2)(g)to4NO(g)+6H_(2)O(g) If the rate of formation of NO is 3.6xx10^(-3)molL^(-1)s^(-1),calculate (i) the rate of disappearance of NH_(3). (ii)the rate of formation of H_(2)O |
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Answer» SOLUTION :`(i)` Rate of reaction `=-(1)/(4)(d[NH_(3)])/(dt)=-(1)/(5)(d[O_(2)])/(dt)=(1)/(4)(d[NO])/(dt)=+(1)/(6)(d[H_(2)O])/(dt)` Rate of DISAPPEARANCE of `NH_(3)=` Rate of formation of `NO` `=3.6xx10^(-3)mol L^(-1)s^(-1)` Rate of formation of `H_(2)O=(6)/(4)xx` Rate of formation of `NO` `IMPLIES(d[H_(2)O])/(dt)=(3)/(2)xx3.6xx10^(-3)` `=5.4xx10^(-3)molL^(-1)s^(-1)`. |
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