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Eye detects the green light (lamda=5000Å),5xx10^(4) photons per square metre per second and the ear can detect 10^(-13) watt per square metre. In form of power 10^(-13) watt per square metre. In form of power detector, the eye is sensitive in comparison to the ear by

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Solution :Energy of green photon, `E=(hc)/(lambda)`
`=((6.6xx10^(-34))(3XX10^(8)))/((5000xx10^(-10)))=(3.96xx10^(-19))J`
Energy received per second `=(3.96xx10^(-19))(5xx10^(4))`
`=1.98xx10^(-14)W//m^(2)`
Sensitivity of eye in COMPARISON to ear=
`=("Power per square METRE detected by ear")/("Energy received per second")`
`=(10^(-13))/((1.98xx10^(-14)))=5`


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