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F-1. A particle moving with kinetic energy K makes a head on elastic collision with an identical particle atrest. Find the maximum elastic potential energy of the system during collision. |
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Answer» let the mass of the particles be m and v be its velocity. then 0.5mv^2=k.in an elastic collision, the k.e. before and after the collision remains the same and is minimum when the two particles are moving with the same speed, during collision.applying momentum conservationmv+0=(m+m)VV=v/2K.E.=0.5*2m*V^2= (0.5*m*v^2)/2 = k/2 (the kinetic energy when both masses are moving with same speed, at this moment k.e. is minimum and p.e. is maximum)P.E.+ K.E.= kP.E.= k/2. |
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