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F_(2) is a stronger oxidising agent than CI_(2). |
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Answer» Solution :The elcetrode potential of `F_(2) and Cl_(2)` are : `F_(2) + 2e^(-) rarr 2 F^(-) , E^(@) = + 2.87 V and Cl_(2) + 2e^(-) rarr 2 Cl^(-) , E^(@) = 1.36 V` Since `E^(@)` for `F_(2)//F^(-)` electrode is higher than that of `Cl_(2)//Cl^(-)` electrode, therefore, `F_(2)` is more EASILY reduced than `Cl_(2)`. In other words, `F_(2)` is a stronger oxidising agent than `Cl_(2)`. For example, `F_(2)` OXIDISES `CL^(-)` IONS to `Cl_(2)` but `Cl_(2)` does not oxide `F^(-)` ions to `F_(2)`. 
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