1.

`f : C to R : f (z) =|z|` isA. one-one and intoB. one -one and ontoC. many -one and intoD. many -one and onto

Answer» Correct Answer - C
`I ne -i`. But f(i) `=f(-i) =1. `so f is many -one
`-1 in R` having no pre-image in C. So f is into.


Discussion

No Comment Found