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| 1. |
`f : C to R : f (z) =|z|` isA. one-one and intoB. one -one and ontoC. many -one and intoD. many -one and onto |
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Answer» Correct Answer - C `I ne -i`. But f(i) `=f(-i) =1. `so f is many -one `-1 in R` having no pre-image in C. So f is into. |
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