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`f : R^(+) to R^(+) : f(x) = e^(x) ` isA. many-one and intoB. many -one and ontoC. one-one and intoD. one-one and onto |
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Answer» Correct Answer - D `f(x_(1)) =f(x_(2)) rArr e^(x_(1)) =e^(x_(2)) rArr x_(1) =x_(2)` . So f is one-one For each `x in R^(+) EE " log " x in R^(+) s.t f(log x )=x` `So , f in onto. |
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