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f(x) = \(\sqrt{9-x^2}\). Find the range of the function.(a) R(b) R^+(c) [-3,3](d) [0,3]I got this question in homework.This key question is from Functions topic in section Relations and Functions of Mathematics – Class 11

Answer»

The correct CHOICE is (d) [0,3]

EXPLANATION: We know, SQUARE root is always non-negative. So, \(\sqrt{9-x^2}\) ≥ 0. So, range of the FUNCTION is set of positive real NUMBERS.



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