1.

f(x)=x^{2}+3 x-5 A=\left[ \begin{array}{rr}{2} & {-1} \\ {4} & {3}\end{array}\right]

Answer»

A^2=A*A=2*2-1*4 2*(-1)+(-1)*3 4*2+3*4 4*(-1)+3(3) =0 -5 20 5A^2+3A-5I=0+6-5 -5-3 20+12 5+9-5 =1 -8 32 9



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