1.

Factorise 27 a cube + b cube + c cube - 18abc using identity

Answer»

Hi ,

Plz , there is an error in the QUESTION.

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We know the algebraic IDENTITY,

x³ + y³ + z³ - 3xyz

= ( x + y + Z )( x² + y² + z² - xy - YZ - zx )

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Now ,

27a³ + b³ + c³ - 9abc

= ( 3a )³ + b³ + c³ - 3 × 3a × b × c

= (3a + b + c )[(3a)²+b²+c² -3ab-bc-3ac]

= (3a+b+c)[9a²+b²+c²-3ab-bc-3ac]

I HOPE this helps you.

: )


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