1.

Factorise (2a+3b)^3-27c^3​

Answer»

(2a+3b)³ - 27c³ = (2a+3b-3C)(2a+3b)²+9c²+(2a+3b)(3c) = (2a+3b-3c)(4a²+9b²+9c²+12ab+6ac+9bc)



Discussion

No Comment Found

Related InterviewSolutions