InterviewSolution
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InterviewSolution
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Factorise : 2a+6b−3(a+3b)22a+6b−3(a+3b)2=2(a+3b)−3(a+3b)2 [Taking 2 common from 2a+6b]=(a+3b){2−3(a+3b)} [Taking (a+3b) common]=(a+3b)(2−3a−9b) |
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Answer» Factorise : 2a+6b−3(a+3b)2 2a+6b−3(a+3b)2 =2(a+3b)−3(a+3b)2 [Taking 2 common from 2a+6b] =(a+3b){2−3(a+3b)} [Taking (a+3b) common] =(a+3b)(2−3a−9b) |
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