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Factorise 2x^3+9x^2+4x-12​

Answer» X= -2,    (-5+sqrt(73))/4    ,     (-5-sqrt(73))/4Step-by-step EXPLANATION:hit and trail method:f(-2)=2(-2)^3+9(-2)^2+4(-2)-12        =2(-8)+9(4)-8-12     =-16+36-8-12    =0so x+2 is one factor(2x^3+9x^2+4x-12)/(x+2)we get 2x^2+5x-6factorize we get (-5+sqrt(73))/4    ,      (-5-sqrt(73))/4


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