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Factorise (49x^2-126x+81)-31 |
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Answer» Answer: Equation at the end of step 1 : (72x2 - 126x) + 81 Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 49x2-126x+81 The first term is, 49x2 its coefficient is 49 . The middle term is, -126x its coefficient is -126 . The last term, "the constant", is +81 Step-1 : Multiply the coefficient of the first term by the constant 49 • 81 = 3969 Step-2 : Find TWO factors of 3969 whose sum equals the coefficient of the middle term, which is -126 . -3969 + -1 = -3970 -1323 + -3 = -1326 -567 + -7 = -574 -441 + -9 = -450 -189 + -21 = -210 -147 + -27 = -174 -81 + -49 = -130 -63 + -63 = -126 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -63 and -63 49x2 - 63x - 63x - 81 Step-4 : Add up the first 2 terms, pulling out like factors : 7x • (7x-9) Add up the last 2 terms, pulling out common factors : 9 • (7x-9) Step-5 : Add up the four terms of step 4 : (7x-9) • (7x-9) Which is the desired factorization Multiplying Exponential Expressions : 2.2 Multiply (7x-9) by (7x-9) The rule says : To multiply exponential expressions which have the same base, add up their exponents. In our case, the common base is (7x-9) and the exponents are : 1 , as (7x-9) is the same number as (7x-9)1 and 1 , as (7x-9) is the same number as (7x-9)1 The product is therefore, (7x-9)(1+1) = (7x-9)2 Final result : (7x - 9)2 Step-by-step explanation: |
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