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Factorise 4a²- 18a - 16 by splitting the middle term.please give me right answer. |
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Answer» Answer: STEP 1 : Equation at the end of step 1 (22a2 - 18a) - 36 STEP 2 : STEP 3 : PULLING out like terms 3.1 Pull out like factors : 4a2 - 18a - 36 = 2 • (2a2 - 9A - 18) Trying to FACTOR by splitting the middle term 3.2 Factoring 2a2 - 9a - 18 The first term is, 2a2 its COEFFICIENT is 2 . The middle term is, -9a its coefficient is -9 . The last term, "the constant", is -18 Step-1 : Multiply the coefficient of the first term by the constant 2 • -18 = -36 Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is -9 . -36 + 1 = -35 -18 + 2 = -16 -12 + 3 = -9 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 3 2a2 - 12a + 3a - 18 Step-4 : Add up the first 2 terms, pulling out like factors : 2a • (a-6) Add up the last 2 terms, pulling out common factors : 3 • (a-6) Step-5 : Add up the four terms of step 4 : (2a+3) • (a-6) Which is the desired factorization Final RESULT : 2 • (a - 6) • (2a + 3) |
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