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Factorise 8a3 + b3 +12a2b + 6ab2

Answer»

we can also write 8a³ + b³ + 12a²b + 6ab² as  (2A)³+(B)³+3(2a)³(b)+3(2a)(b)8a³+b³+12a²b+6ab² =  (2a)³+(b)³+3(2a)³(b)+3(2a)(b)= ( 2a + b )³= (2a+b) (2a +b) (2a +b)Here identity, (x+y)³ = x³ + y³ + 3xy(x+y)



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