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Factorise:(a^2-b^2)(c^2-d^2)-4abcd |
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Answer» (a^2-b^2)(c^2-d^2)-4abcd=a^2(c^2-d^2)-b^2(c^2-d^2)-4abcd=a^2c^2-a^2d^2-b^2c^2+b^2d^2-4abcd=a^2c^2+b^2d^2-2abcd-a^2d^2-b^2c^2-2abcd=(a^2c^2+b^2d^2-2abcd)-(a^2d^2+b^2c^2+2abcd)=(ac-bd)^2-(ad+bc)^2=(ac-bd+ad+bc)(ac-bd-ad-bc) Ans.Step-by-step explanation:I HOPE IT WILL HELP YOU MARK IT AS THE BRAINLIEST PLEASE |
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