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Factorise:-a^3-18a^2+108a-216Answer it fast please please |
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Answer» Answer: (a - 6)^3 Step-by-step explanation: Given, a^3 - 18a^2 + 108a - 216 F(a) = a^3-18a^2+108a-216 Polynomial Roots Calculator is a set of methods aimed at FINDING VALUES of a for which F(a)=0 Rational Roots Test is ONE of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient In this case, the Leading Coefficient is 1 and the Trailing Constant is -216. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,8 ,9 ,12 ,18 ,24 , etc. In our case this means that a^3-18a^2+108a-216 can be divided with a-6 . On dividing a^3-18a^2+108a-216 by (a-6), we get a^2 - 12a + 36. So now, p(X) = a^2 - 12a + 36. On splitting the middle TERM, we get, a^2 - 6a - 6a + 36 = 0 => a(a - 6) -6(a - 6) = 0 => (a - 6)(a - 6) = 0 Here, either (a - 6) or (a - 6) is equal to zero. => (a - 6) = 0 or (a - 6) = 0 So, => a = 6 or 6 => a = 6 Thus by multiplying exponentials, we get, (a - 6)^3. a^3 - 18a^2 + 108a - 216 = (a - 6)^3 |
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